the following command was not found netsh

Question

I'm trying execute a couple of "netsh" commands but no matter what I do I keep getting the same error "the following command was not found netsh".

I can verify that the path "C:\Windows\System32\netsh.exe" is valid and when I run the same command with the same set of arguments through the command prompt; everything works fine.

This a sample of the code I'm using.

ProcessStartInfo procInfo = new ProcessStartInfo
            {
                WorkingDirectory = System.IO.Path.GetPathRoot(System.Environment.SystemDirectory),
                FileName = @"netsh.exe",
                RedirectStandardOutput = true,
                RedirectStandardError = true,
                UseShellExecute = false,
                CreateNoWindow = true,
                Arguments = String.Format(@"{0}\{1} {2}", System.Environment.SystemDirectory, @"netsh.exe", "wlan start hostednetwork"),
                WindowStyle = ProcessWindowStyle.Hidden
            };

            Process proc = Process.Start(procInfo);
            proc.WaitForExit();

Answer 1

You're currently passing the full pathname in the arguments, when I suspect you want to pass it as the filename. For example:

FileName = Path.Combine(Environment.SystemDirectory, "netsh.exe"),
Arguments = "wlan start hostednetwork"

For example, this short but complete program doesn't throw any exceptions - I don't know whether it does what you want, but it doesn't fail with the exception you described:

using System;
using System.Diagnostics;
using System.IO;

class Test
{    
    static void Main()
    {
        ProcessStartInfo procInfo = new ProcessStartInfo
        {
            WorkingDirectory = Path.GetPathRoot(Environment.SystemDirectory),
            FileName = Path.Combine(Environment.SystemDirectory, "netsh.exe"),
            Arguments = "wlan start hostednetwork",
            RedirectStandardOutput = true,
            RedirectStandardError = true,
            UseShellExecute = false,
            CreateNoWindow = true,
            WindowStyle = ProcessWindowStyle.Hidden
        };

        Process proc = Process.Start(procInfo);
        proc.WaitForExit();
    }
}

(Note how the code becomes less cluttered when you take advantage of using directives instead of using fully-qualified names, by the way.)