So how can I make it such that fetchMyData() will display the ajax result once it's ready?
You've already done that, in the .done
callback. If you want fetchMyData
to return the response, you have to use a synchronous call, which is usually not the right thing to do (because the UI will freeze until the response arrives).
Maybe you want to modify your function to take a callback:
function fetchMyData(thenDoThis){
$.ajax({
// ajax setup
}).done(thenDoThis)
}
function doSomethingWithResponse(response) {
// do something
}
Then call it like this:
fetchMyData(doSomethingWithResponse);
Or like this:
$('<div>').click(function() {
fetchMyData(function(response){
console.log(response);
});
});