Use rle
:
test = c(0,0,0,2,1,5,3)
rle_test = rle(test)
ordered = rep(1:length(rle_test$lengths), rle_test$lengths)
Output:
> ordered
[1] 1 1 1 2 3 4 5
Question
I want to rank a column of a data frame but I want it to be ranked based on its order not ascending or descending order. Something like below:
> test <- c(0,0,0,2,1,5,3)
and then rank like this:
[1] 1 1 1 2 3 4 5
What is the easiest way of doing it? Thank you in advance.
Solution
Use rle
:
test = c(0,0,0,2,1,5,3)
rle_test = rle(test)
ordered = rep(1:length(rle_test$lengths), rle_test$lengths)
Output:
> ordered
[1] 1 1 1 2 3 4 5
OTHER TIPS
An alternative would use the ties="dense" option of frankv() in data.table package:
x
[1] 12 9 5 7 15 7 7 8 7 13 6 12 7 12 5 2 8 28 20 9 10 3 12 6 1
frankv(x,ties="dense")
[1] 10 8 4 6 12 6 6 7 6 11 5 10 6 10 4 2 7 14 13 8 9 3 10 5 1