If an input has the disabled='true'
property at the moment of form submit, it's value isn't submited with the form. You can either try to re-enable it at the moment of form submit in jQuery, like:
$("#yourFormId").submit(function(){
$("#YourInputId").prop('disabled', 'false');
});
Another approach is to use many extra hidden fields for each "visible" input, like <input id='hiddenInputId' type='hidden' >
and to set thier values in jQuery. They will not be seen by the user, but their values will still be sent with form submit. Example:
$("#yourInputId").change(function(){
$("#hiddenInputId").val($(this).val()));
});
After that, when you process the submit, you just ignore regular input values and only work with hiddens.
Personally, I think that the second option (with hidden inputs) is much better. You can even extend it, and instead of hard-typing your DOM element id in change(), you can add a data-attribute to each element and then kill all birds with one stone :)