in psuedocode:
point dif = currentPt - previousPt
float distance = sqrt(dif.x * dif.x + dif.y * dif.y)
float newCurrentX = previousPt.x + distance * cos(newAngle)
floar newCurrentY = previousPt.y + distance * sin(newAngle)
However, if all the new angles are multiples of 45, you could avoid using sin and cos.
For a multiple of 90 degress (or zero degrees),
if (newAngle is 90) newCurrentY = previousPt.y + distance
else if (newAngle is 0) newCurentX = previousPt.x + distance,
etc.
for multiples of 45 degress:
else if (newAngle is 135) {
shift = distance * CONST_SIN_OF_45;
newCurrentX = previousPt.x - shift;
newCurrentY = previousPt.y + shift;
}