From the OutputStream.write(int)
doc:
Writes the specified byte to this output stream. The general contract for write is that one byte is written to the output stream. The byte to be written is the eight low-order bits of the argument b. The 24 high-order bits of b are ignored.
Emphasis mine.
Note that the method takes an int
. And since 100000 is a valid integer literal, there is no point of it being not compiling.