Question

I have a web service with an ever growing number of TWebAction items defined at design time on a TWebModule, and coupled to OnAction events.

Requests are HTTP GETs through the URL and responses are 'handcrafted' JSON data, i.e. composed at runtime with statement like 'TSuperObject'.S['errormessage'] := lErrMsg;
I want to change this to HTTP POST requests with JSON data, and then all request/response JSON structures being (de)serialized from/to proper Objects (and maybe records) using SuperObjects TSuperRttiContext AsJSON and AsType methods.

How can I create data structures for mapping/linking my new 'Objects to be JSON (de)serialized' with the design time TWebactions? These objects will all be different (some properties can be in a common ancestor), and may contain object or record properties themselves (things like FData: Array of TSubObject [which SuperObject can serialize fine]).

Note: There is already a quick-and-dirty enumerated type that I have used to gather timing statistics (which needs to be maintained too), this could be integrated as well.

type
   TWebAct = (
    ttinfo,
    ttlogin,
    ...
    ttgetcostitemlist,
    ttgetvacationplanning
    );

Basically, I want to minimize the number of places where I need to do maintenance whenever a new TWebAction is added.

Was it helpful?

Solution

You can use the TWebAct enumeration to put together an array of records that tie the web actions to their respective request and response structures.

type
  // ancestor class for all requests and responses
  TJSONStructure = class(TObject);

  TJSONRequest = class(TJSONStructure);
  TJSONRequestClass = class of TJSONRequest;

  TJSONResponse = class(TJSONStructure);
  TJSONResponseClass = class of TJSONResponse;

const 
  WEBACT_STRUCTURES: array[TWebAct] of 
    record
      RequestClass: TJSONRequestClass;
      ResponseClass: TJSONResponseClass;
    end = (
      {ttInfo}   (RequestClass: TInfoRequest; ResponseClass: TInfoResponse)
    , {ttLogin}  (RequestClass: TLoginRequest; ResponseClass: TLoginResponse)
    ...
  );
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