How to partition a MySQL table based on char column?

https://stackoverflow.com/questions/3753317

04-10-2019
|

Question

Is it possible to partition based on char column?

After reviewing the MySQL 5.1 documentation it appears that only integer types can be used.

Is this correct? Or can I use some function to convert the char into an integer?

The char field in question contains a unique identifier.

Solution

Partitioning in MySQL 5.1 can only deal with integer columns (Source). You can only use a few partitioning functions on non-integer columns. For example:

CREATE TABLE ti (id INT, amount DECIMAL(7,2), tr_date DATE)
   ENGINE=INNODB
   PARTITION BY HASH( MONTH(tr_date) )
   PARTITIONS 6;

You can also use key partitioning in MySQL 5.1, as long as the primary key includes all the columns in the table's partitioning function:

CREATE TABLE k1 (
   id CHAR(3) NOT NULL PRIMARY KEY,
   value int
)
PARTITION BY KEY(id)
PARTITIONS 10;

On the other hand, in MySQL 5.5, you can use range column partitioning or list column partitioning on a wide variety of data types, including character-based columns.

List Columns Example:

CREATE TABLE expenses (
   expense_date DATE NOT NULL,
   category VARCHAR(30),
   amount DECIMAL (10,3)
);

ALTER TABLE expenses
PARTITION BY LIST COLUMNS (category)
(
   PARTITION p01 VALUES IN ('lodging', 'food'),
   PARTITION p02 VALUES IN ('flights', 'ground transportation'),
   PARTITION p03 VALUES IN ('leisure', 'customer entertainment'),
   PARTITION p04 VALUES IN ('communications'),
   PARTITION p05 VALUES IN ('fees')
);

Range Columns Example:

CREATE TABLE range_test (
   code CHAR(3),
   value INT
)
PARTITION BY RANGE COLUMNS(code) (
   PARTITION p0 VALUES LESS THAN ('MMM'),
   PARTITION p1 VALUES LESS THAN ('ZZZ')
);