Question

I build a WebView which displays a website. The website contains links without a target="_blank" attribute and some with it.

I need to open the links with target defined in the external standard device browser and the ones without it inside the WebView.

I'm using a WebViewClient and I tried around with this function but still all my links are opened within the WebView:

Alternative 1:

@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {

    return super.shouldOverrideUrlLoading(view, url);        
}

Alternative 2:

@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {

    view.loadUrl(url);
    return true;        
}

Does anybody know how I can open blank-links externally?

Thanks!

PS: To avoid missunderstandings: I can't use this approach because the only way I know the link should be opened externallly is the target attribute.

Was it helpful?

Solution

After visiting the above links, I come up with this code and hope this helps.

wv.getSettings().setSupportMultipleWindows(true);
wv.setWebChromeClient(new WebChromeClient() {
    @Override
    public boolean onCreateWindow(WebView view, boolean dialog, boolean userGesture, android.os.Message resultMsg)
    {
        WebView.HitTestResult result = view.getHitTestResult();
        String data = result.getExtra();
        Context context = view.getContext();
        Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(data));
        context.startActivity(browserIntent);
        return false;
    }
});

OTHER TIPS

I faced same problem. I wanted to open my web sites pages inside the application and rest all the pages should be open in Default Browser. I used one technique. If URL contains my website name, then I opened it in WebView and rest all the websites opened in Default browser.

Find Below code, I hope It would be useful for all who faced such problems.

private class MyBrowser extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (url.contains("/internetgeeks")) {
            browser.loadUrl(url);
            return false;
        } else {
            Intent intent = new Intent(Intent.ACTION_VIEW);
            intent.setData(Uri.parse(url));
            startActivity(intent);
            return true;
        }
    }
}

I also have the same problem and now I've found the solution.

You also need to use WebChromeClient.You can see this and this . And you can set a WebViewClient to the new WebView and override the shouldOverrideUrlLoading method, then you can get the url and do whatever you want here. If you don't set the WebViewClient, I think it should works too. In my case I want to get the url so I set a WebViewClient to the new WebView.

By the way, if you remove the old webview then when you come back form the browser,the webview is blank. So I retained the webview and added a new one but set the visibility to "gone".

If you wanted to do it using only Javascript, then this is my solution for opening any link from webview of the android or ios app to the external browser.

Modified your URL with this 'open=outside' in query params.

ie. https://example.com/homePage?open=outside

private  WebView WEB_v;

if you open new window when you click a link any 2nd window, then it I will open by another browser

 WEB_v.getSettings().setSupportMultipleWindows(true);
    WEB_v.setWebChromeClient(new WebChromeClient() {
        @Override
        public boolean onCreateWindow(WebView view, boolean dialog, boolean userGesture, android.os.Message resultMsg)
        {
            WebView.HitTestResult result = view.getHitTestResult();
            String data = result.getExtra();
            Context context = view.getContext();
            Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(data));
            context.startActivity(browserIntent);
            return false;
        }
    });
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