How can I convert JSON boolean values for output using XMLout?
-
06-07-2019 - |
Question
There are boolean values in the JSON data structure I am using. When call decode_json
to convert it to a Perl data structure and feed to the XMLout
function provided by XML::Simple
, it throws an error because XMLout
does not know how to deal with JSON::XS::Boolean
values.
Is there a way to convert the JSON::XS::Boolean
values in a data structure to XML?
my $text = '{"a":"x","b":true}';
my $result = decode_json($text);
my $rec = XMLout( $result, RootName => 'root', SuppressEmpty => 1);
In the code abive, I get the following error - Can't encode a value of type: JSON::XS::Boolean
A print Dumper $result
gives:
$result = {
'a' => 'x',
'b' => bless( do{\(my $o = 1)}, 'JSON::XS::Boolean' )
};
Solution
I asked the same question on PerlMonks and am reproducing the proposed solution below.
Basically, the solution is to change the value of JSON::XS::Boolean to an appropriate value before passing it to XMLout:
use strict;
use warnings;
use JSON;
use XML::Simple;
my $text = '{"a":"x","b":true}';
my $result = decode_json($text);
for my $value ( values %$result ) {
next unless 'JSON::XS::Boolean' eq ref $value;
$value = ( $value ? 'true' : 'false' );
}
print XMLout( $result, RootName => 'root', SuppressEmpty => 1);
Output:
C:\Temp> test.pl
<root a="x" b="true" />
OTHER TIPS
Edit: I wrote this answer before all the edits to the original question. The question as stated now is that the original poster wants to create an XML-ready structure for using with XML::Simple; originally stated, it seemed that he just wanted to put the JSON structure in a text node.
Perl objects need to be JSON-encoded before sending them through the wire.
From your example:
my $text = '{"a":"x","b":true}';
my $result = decode_json($text);
print JSON->new->utf8->pretty(1)->encode($result);
You get the following:
$ perl json.pl
{
"a" : "x",
"b" : true
}