This is what I probably would do:
typedef ::std::vector<int> MyList;
typedef MyList::iterator MyListIter;
MyList data;
// ... fill data ...
const int searchValue = 2;
const int addValue = 3;
// Find first occurence of searched value
MyListIter iter = ::std::find(data.begin(), data.end(), searchValue);
while(iter != data.end())
{
// We want to add our value after searched one
++iter;
// Insert value and return iterator pointing to the inserted position
// (original iterator is invalid now).
iter = data.insert(iter, addValue);
// This is needed only if we want to be sure that out value won't be used
// - for example if searchValue == addValue is true, code would create
// infinite loop.
++iter;
// Search for next value.
iter = ::std::find(iter, data.end(), searchValue);
}
but as you can see, I couldn't avoid the incrementation you mentioned. But I don't think that would be bad thing: I would put this code to separate functions (probably in some kind of "core/utils" module) and - of course - implement this function as template, so I would write it only once - only once worrying about incrementing value is IMHO acceptable. Very acceptable.
template <class ValueType>
void insertAfter(::std::vector<ValueType> &io_data,
const ValueType &i_searchValue,
const ValueType &i_insertAfterValue);
or even better (IMHO)
template <class ListType, class ValueType>
void insertAfter(ListType &io_data,
const ValueType &i_searchValue,
const ValueType &i_insertAfterValue);
EDIT:
well, I would solve problem little different way: first count number of the searched value occurrence (preferably store in some kind of cache which can be kept and used repeatably) so I could prepare array before (only one allocation) and used memcpy to move original values (for types like int only, of course) or memmove (if the vector allocated size is sufficient already).