Exceeding unsigned boundary [closed]

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Closed 8 years ago.

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#include <stdio.h>
int main ()
{
unsigned char a=250,b=20, c;
c=a+b;
printf ("%d\n",c);
return 0;
}

What can I do for it to show 270? Besides declaring c as int.

Answer 1

Unsigned char's (assuming char is only eight bits) can only represent 2⁸ numbers, from 0 to 255. You'll need to use another type such as int to represent this.

Answer 2

I'm sorry but you just can't , an unsigned char can hold a maximum of 255