logging.INFO
denotes an integer constant with value of 20
INFO Confirmation that things are working as expected.
What you need is logging.info
logging.info("test")
Question
Could you please help me, whats wrong.
import logging if (__name__ == "__main__"): logging.basicConfig(format='[%(asctime)s] %(levelname)s::%(module)s::%(funcName)s() %(message)s', level=logging.DEBUG) logging.INFO("test")
And I can't run it, I've got an error:
Traceback (most recent call last): File "/home/htfuws/Programming/Python/just-kidding/main.py", line 5, in logging.INFO("test") TypeError: 'int' object is not callable
Thank you very much.
Solution
logging.INFO
denotes an integer constant with value of 20
INFO Confirmation that things are working as expected.
What you need is logging.info
logging.info("test")
OTHER TIPS
You are trying to call logging.INFO
, which is an integer constant denoting one of the pre-defined logging levels:
>>> import logging
>>> logging.INFO
20
>>> type(logging.INFO)
<type 'int'>
You probably wanted to use the logging.info()
function (note, all lowercase) instead:
Logs a message with level
INFO
on this logger. The arguments are interpreted as fordebug()
.