One way to grab all rows where the first letter of the second word is capital
SELECT t.*, SUBSTRING_INDEX(SUBSTRING_INDEX(column1, ' ', 2), ' ', -1) second_word
FROM Table1 t
WHERE CHAR_LENGTH(column1) - CHAR_LENGTH(REPLACE(column1, ' ', '')) > 1
HAVING BINARY LEFT(second_word, 1) = BINARY UPPER(LEFT(second_word, 1))
Given sample data like this
| ID | COLUMN1 | --------------------------- | 1 | first second third | | 2 | first Second third | | 3 | first | | 4 | NULL |
The output from the query
| ID | COLUMN1 | SECOND_WORD | ----------------------------------------- | 2 | first Second third | Second |
Here is SQLFiddle demo