Jquery .find() - restrictions for where to find

Question

I am using the .find() to find specifiek elements in a div. Now what the .find() does do, is finding every element in that div. I want it only to find it in the first dimension, this means it should not search in div shilds. Now i know there might be a way with :not() as it uses normal selectors.

However, I dont think the .not() is connected with .find(). It doesn't adjust the search function of .find() it only adjusts the selector in the .find() element.

For example:

<div class="content">
  <ul>
     <li><input type="radio" name="radiobutton_1" value="yes"></li>
     <li><input type="radio" name="radiobutton_1" value="no"></li>
  </ul>
  <ul>
     <li><input type="radio" name="radiobutton_2" value="yes"></li>
     <li><input type="radio" name="radiobutton_2" value="no"></li>
  </ul>
  <ul>
     <li><input type="radio" name="radiobutton_2" value="yes"></li>
     <li><input type="radio" name="radiobutton_2" value="no"></li>
  </ul>

   <div class="subcontent" style="displaye: none;">
     <ul>
         <li><input type="radio" name="radiobutton_1_1" value="yes"></li>
         <li><input type="radio" name="radiobutton_1_1" value="no"></li>
     </ul>
     <ul>
         <li><input type="radio" name="radiobutton_2_1" value="yes"></li>
         <li><input type="radio" name="radiobutton_2_1" value="no"></li>
     </ul>
     <ul>
         <li><input type="radio" name="radiobutton_3_1" value="yes"></li>
         <li><input type="radio" name="radiobutton_3_1" value="no"></li>
     </ul>
   </div>
</div>

In this example in want to search for all radiobuttons, however i dont want to search in the div subcontent.

I've also tryed to check separately if the parrent div is :visible, for some odd reason this didn't work properly. So that's why i'm asking for this.

Hope someone could help me, thanks in advance!
- Nkmol

Answer 1

This should work:

$(".content").find(" > ul > li > input[type=radio]");

http://jsfiddle.net/Bb2pY/

Answer 2

try $(div).find(>ul input:radio)