output of a program for returning a string literal from a function

Question

char* fun()
{
  return("samsung india");
}
main()
{
  printf("%s",printf("electronics")+fun());
}

Output: "electronicsia"

could somebody please explain me this output ?

Answer 1

printf("electronics") sends the output to stdout and returns the number of characters printed, which is 11, and since fun() returns a char-pointer, you are adding 11 to that pointer before the outer printf sends it to stdout.

So the inner printf outputs "electronics" and after that the outer printf outputs "ia".

Answer 2

I would say that output can be different on each runtime.. because what happen there:

printf("%s",printf("electronics")+fun());

assume this: printf("%s", arg); where your arg = printf("electronics")+fun()

arg is suposse to be an char* so the pointer... actually when your arg is evaluated, printf("electronics") provide output electronics and return value 11(number of character which was successfully print), your fun() return char* - pointer to memory which points to samsung india, but you add to that pointer 11, so your pointer will be pointing to the "ia" and this add to the output...