Use pg_*
views instead of information_schema
views.
pg_*
views display all information regardles of granted privileges.
Try this query:
select
t.relname as table_name,
i.relname as index_name,
a.attname as column_name,
d.adsrc as default_value
from
pg_class t
join pg_attribute a on a.attrelid = t.oid
join pg_index ix on t.oid = ix.indrelid AND a.attnum = ANY(ix.indkey)
join pg_class i on i.oid = ix.indexrelid
left join pg_attrdef d on d.adrelid = t.oid and d.adnum = a.attnum
where
t.relkind = 'r'
and t.relname in ( 'aa', 'bb', 'cc' )
order by
t.relname,
i.relname,
a.attnum;
An example of the query results:
create table aa(
x int primary KEY
);
create table bb(
x int default 1,
constraint pk primary key ( x )
);
create table cc(
x int default 20,
y varchar(10) default 'something',
constraint cc_pk primary key ( x, y )
);
table_name | index_name | column_name | default_value
------------+------------+-------------+--------------------------------
aa | aa_pkey | x |
bb | pk | x | 1
cc | cc_pk | x | 20
cc | cc_pk | y | 'something'::character varying