Question

I have a Django project, let's say "project1". Typical folder structure for applications is:

/project1/
         /app1/
         /app2/
         ...
         __init__.py
         manage.py
         settings.py
         urls.py

What should I do if I want to hold all of my applications in some separate folder, 'apps' for example? So that structure should look like the following:

/project/
         apps/
              app1/
              app2/
              ...
         __init__.py
         manage.py
         settings.py
         urls.py
Was it helpful?

Solution

You can add your apps folder to your python path by inserting the following in your settings.py:

import os
import sys

PROJECT_ROOT = os.path.dirname(__file__)
sys.path.insert(0, os.path.join(PROJECT_ROOT, 'apps'))

Then you can use all the apps in this folder just in the same way as they were in your project root!

OTHER TIPS

You can do this very easily, but you need to change the settings.py to look like this:

INSTALLED_APPS = (
    'apps.app1',
    'apps.app2',
    # ...
)

And your urls.py to look like this:

urlpatterns = patterns('', 
    (r'^app1/',include('apps.app1')),    
    (r'^app2/',include('apps.app2')),    
)

.. and modify any imports to point to the app location

How about you utilize the BASE_DIR variable already present in the settings.py.

Just add the following:

import sys
sys.path.insert(0, os.path.join('BASE_DIR', 'apps'))

Hope this helps.

If you're using virtualenv/virtualenvwrapper (and you should be), you can use the included add2virtualenv command to augment your python path:

mkdir apps
cd apps
pwd
[/path/to/apps/dir]

Copy that path to clipboard, then:

add2virtualenv /path/to/apps/dir

Just add __init__.py (4 underscores in total) in your apps folder. Now you can just do

urlpatterns = [
        path('polls/',include('apps.polls.urls')),
        path('admin/', admin.site.urls)
]
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