select everything from a table for a column

Question

in my mysql database i have the following tables:

FACULTY (fid int, fname varchar(25), deptid int, primary key(fid))  
CLASS (name varchar(4),meets_at varchar(9),room varchar(4), fid int,primary key (name), foreign key (fid) references faculty (fid))  

I want to select the names of faculties who go to all the rooms. I tried using following :

SELECT DISTINCT F.FNAME   
FROM FACULTY F  
WHERE NOT EXISTS (( SELECT *  
FROM CLASS C  
EXCEPT  
(SELECT C1.ROOM  
FROM CLASS C1  
   WHERE C1.FID=F.FID))); 

and got the following error:

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'EXCEPT

also tried with:

SELECT DISTINCT F.FNAME   
FROM FACULTY F   
LEFT JOIN CLASS C ON C.FID = F.FID  
WHERE C.FID IS NULL  

and got "Empty Set" even when in my database there is a faculty who goes to all the rooms.

Answer 1

When you use except the two table must be compatible, try this :

SELECT DISTINCT F.FNAME   
FROM FACULTY F  
WHERE NOT EXISTS (
( SELECT ROOM  
FROM CLASS C)
EXCEPT  
(SELECT C1.ROOM  
FROM CLASS C1  
   WHERE C1.FID=F.FID)
); 

EDIT

The question was tagged to sql server so I gave the answer keeping that in mind, for mysql use this :

SELECT FID, COUNT(*) FROM
(
    (SELECT DISTINCT f.fname, f.fid, c1.room 
    FROM faculty f
    JOIN class c1 
    ON f.fid = c1.fid) tb1 
JOIN
    (SELECT DISTINCT room AS room2 FROM class) tb2
ON tb1.room = tb2.room2
)
GROUP BY FID
HAVING COUNT(*) IN (SELECT COUNT(DISTINCT Room) FROM Class);

fiddle:http://sqlfiddle.com/#!8/cff12/4

Answer 2

My point of view related to your problem.

SELECT T.fid FROM
  (SELECT f.fid FROM 
     faculty f LEFT JOIN class c ON f.fid = c.fid) T
  GROUP BY T.fid 
  HAVING(
    COUNT(T.fid) = (SELECT COUNT(DISTINCT room) FROM class))

SQL fiddle