Python: Handle Missing Files from a Sequence

Question

I have a program that's basically as follows:

for l in range(0,100):  
 file = open("C:/Twitter/json/user_" + str(l) + ".json", "r")
 #do some stuff
 file.close()

I am trying to figure out a way to handle the exception that will be thrown if say file 20 is missing, and tell it to continue. I attempted to use the continue with a try statement however, it kept complaining that I wasn't putting it in the loop properly. Any advice would be appreciated.

Basically I tried:

try:
 for:
except:
 continue

Thanks,

Answer 1

Something like :

import json
for l in xrange(100):
    try:
        with open('C:/Twitter/json/user_%d.json' % l, 'r') as f:
            data = json.load(f)
            #do stuff with obj
    except IOError:
        pass

edit fixed the code.

Answer 2

you could check file existence and then open it:

import os.path
os.path.exists(file_path)