Assuming you want an equivalent formula you have to use transformations that preserves logical equivalence.
Here is a potential first step;
A ∨ (B ∧ C) ∨ (D ∧ E ∧ ¬(A ∨ B))
((A ∨ B) ∧ (A ∨ C)) ∨ (D ∧ E ∧ ¬A ∧ ¬B)
Taking distribution laws for A ∨ (B ∧ C) and applying DeMorgan to ¬(A ∨ B)