Omit one parameter from view in Django?

Question

In urls.py urlpatterns I have such declaration:

url(r'^product-(\d+)-([a-zA-Z_]+)$', 'product', name="product"),

Second group in regexp is SEO name not needed in view.

In view I have:

def product(request, product_id, suffix):

but suffix is neither required nor used by me. It's there only for SEO.

Is there any way to get rid of this parameter?

Answer 1

Remove the parenthesis around the SEO name:

url(r'^product-(\d+)-[a-zA-Z_]+$', 'product', name="product"),

Now the pattern will not be captured and passed on to your view.

If grouping is required, use a non-capturing group ((?:...) instead of (...)):

url(r'^product-(\d+)-(?:[a-zA-Z_]+)$', 'product', name="product"),