Question
How to handle nested lists in Python? I am having problem figuring out the syntax. Like example:
>>> l = [[1, 2, 3], [5, 6, 7]]
I want to square all the elements in this list. I tried:
[m*m for m in l]
But that doesn't work and throws up:
TypeError: can't multiply sequence by non-int of type 'list'
because of the nested lists I guess?
How do I fix this?
Solution
>>> l = [[1, 2, 3], [5, 6, 7]]
>>> [[e*e for e in m] for m in l]
|-nested list-|
|---- complete list ---|
[[1, 4, 9], [25, 36, 49]]
OTHER TIPS
[[1,2,3],[4,5,6]] != [1,2,3,4,5,6]
[map(lambda x: x *x,sl) for sl in l] #List comprhension
What you need is a recursive function, something like this:
def square(el):
if type(el) == list:
return [square(x) for x in el]
else:
return el**2;
I'd rather not get into the correctness of type(el) == list
here, but you get the gist.
Of course, this is also doable with a list-comprehension, as many people have pointer out, provided that the structure is always the same. This recursive function can handle any level of recursion, and lists containing both lists and numbers.
Assuming you wanted the answer to look like this:
[[1, 4, 9], [25, 36, 49]]
You could do something like this:
l = [[1, 2, 3], [5, 6, 7]]
for x in range(len(l)):
for y in range(len(l[x])):
l[x][y] = l[x][y] * l[x][y]
print l
Obviously, the list comprehension answer is better.