Getting pointer to boost::any::operator=

Question

I want to get pointer to boost::any::operator=, so i did this:

bool(__thiscall boost::any::*func)(const bool&) = &(boost::any::operator=<bool>);

but now, compiler says

initializing' : cannot convert from 'overloaded-function' to 'bool (__thiscall boost::any::* )(const bool &)' None of the functions with this name in scope match the target type

i also tried to make it this way:

bool(__thiscall boost::any::*func)(const bool&) = static_cast<(boost::any::*)(const bool&)>(&(boost::any::operator=<bool>));

but there is compiler says: "syntax error : '('" in this line

can anybody helps me, please?

P.S. I make instaces of boost::any in the code above

Answer 1

You can not specify the arguments in the assignment of the member function pointer. This will do it:

#include <iostream>
#include <boost/any.hpp>
int main() {
    boost::any any = false;
    std::cout << boost::any_cast<bool>(any) << std::endl;
    typedef boost::any& (boost::any::*assign_operator)(const bool&);
    assign_operator assign = &boost::any::operator =;
    (any.*assign)(true);
    std::cout << boost::any_cast<bool>(any) << std::endl;
    return 0;
}