PHP if(){} does not echoes vars got from html [closed]

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All I need is: 1. After pressing 'submit' button to get vars to function and use return value. 2. To understand why I can not echo functions return value;

PHP FUNCTION:

function check_if_numbers($x, $y)
{   
        $permission =0;
        if((gettype($x)==gettype($y))&&(gettype($x)=="integer")) {return 1;}
        else {return 0;}
}

PHP CODE

<?php
    if( isset($_GET['submit']) )
    {
        $x = htmlentities($_GET['x']);
        $y = htmlentities($_GET['y']);
        $permission_token=check_if_numbers($x, $y);
        echo $permission_token;
    }
?>

HTML

<form action="" method="get">
Determine X = <input name='x' id='x' type="text" size="1"></br>
Determine Y = <input name='y' id='y' type="text" size="1"></br>
<font size=2 >Input only integers</font>
<input type="submit" value="submit">

Answer 1

You forgot to name your submit button, that's why $_GET['submit'] is never set:

<input type="submit" value="submit" name="submit" />   

Remove these closing </input> - they are all incorrect.

Answer 2

A c is missing when you call chek_if_numbers and not check_if_numbers.

Answer 3

2 To understand why I can not echo functions return value;

For old versions of PHP (before 4.3 I think), PHP will echo zero (ie echo(0);) as boolean false and not 0, and as such it will not display anything on the screen.