Go back to basics. You read my article; read it again. The two ironclad rules that are relevant to your situation are:
- if x equals y then the hash code of x must equal the hash code of y. Equivalently: if the hash code of x does not equal the hash code of y then x and y must be unequal.
- the hash code of x must remain stable while x is in a hash table.
Those are requirements for correctness. If you can't guarantee those two simple things then your program will not be correct.
You propose two solutions.
Your first solution is that you always return a constant. That meets the requirement of both rules, but you are then reduced to linear searches in your hash table. You might as well use a list.
The other solution you propose is to somehow produce a hash code for each object and store it in the object. That is perfectly legal provided that equal items have equal hash codes. If you do that then you are restricted such that x equals y must be false if the hash codes differ. This seems to make value equality basically impossible. Since you wouldn't be overriding Equals in the first place if you wanted reference equality, this seems like a really bad idea, but it is legal provided that equals is consistent.
I propose a third solution, which is: never put your object in a hash table, because a hash table is the wrong data structure in the first place. The point of a hash table is to quickly answer the question "is this given value in this set of immutable values?" and you don't have a set of immutable values, so don't use a hash table. Use the right tool for the job. Use a list, and live with the pain of doing linear searches.
A fourth solution is: hash on the mutable fields used for equality, remove the object from all hash tables it is in just before every time you mutate it, and put it back in afterwards. This meets both requirements: the hash code agrees with equality, and hashes of objects in hash tables are stable, and you still get fast lookups.