I found this post while searching to see if SQLite had a weekday function. If you use the top answer you're not likely to get a very solid value for days of the week. Here is the code I used for my project, which calculates workdays between ticket creation and closure in SpiceWorks:
SELECT t.id
,t.summary
,t.category
,u.email
,(CAST(strftime('%j', t.closed_at) as INTEGER) - CAST(strftime('%j', t.created_at) as INTEGER) - /*I can't figure it out, but julianday() wasn't giving me the correct distances for some numbers. I used the day of the year, instead, which resolved things as expected*/
CASE
WHEN CAST(strftime('%W', t.closed_at) as INTEGER) - CAST(strftime('%W', t.created_at) as INTEGER) = 0 THEN 0 /*If they are in the same week then there is no weekend to count. If you closed a ticket, that was opened on a Monday, on Saturday, then you must of worked on Saturday and therefore counts as work day the same as if you finished it on Monday*/
WHEN CAST(strftime('%w', t.created_at) as INTEGER) = 0 THEN (CAST(strftime('%W', t.closed_at) as INTEGER) - CAST(strftime('%W', t.created_at) as INTEGER)) * 2 - 1 /*If they made their ticket on Sunday, don't count that Sunday*/
WHEN CAST(strftime('%w', t.created_at) as INTEGER) = 6 THEN (CAST(strftime('%W', t.closed_at) as INTEGER) - CAST(strftime('%W', t.created_at) as INTEGER)) * 2 - 2 /*If they made their ticket on Saturday, don't count that Saturday*/
ELSE (CAST(strftime('%W', t.closed_at) as INTEGER) - CAST(strftime('%W', t.created_at) as INTEGER)) * 2 /*Ignoring the possibility for closed dates that happen before open dates, take the number of weeks between each date and assume each had a Saturday and Sunday within them*/
END) as 'Week Days Elapsed' /*This equation in full represents: Full_Distance_In_Days_Between - Number of weekend days calculated*/
FROM Tickets as t
LEFT JOIN Users as u
on t.created_by = u.id
WHERE strftime('%Y-%m', t.created_at) = strftime('%Y-%m', 'now')