Pregunta

Tengo el siguiente disparador (generado usando php a través de mysqli) ...

DROP TRIGGER IF EXISTS post_queue_insert;
CREATE TRIGGER post_queue_insert AFTER INSERT ON posts
FOR EACH ROW BEGIN
    IF (NEW.post_type != 'revision' AND NEW.post_status != 'auto-draft') THEN
        INSERT INTO event_queue (action_id, action_do, action_key, action_value, action_event, action_timestamp, sync_complete, SITE_ID) VALUES (NEW.ID, 'post', NEW.post_type, NEW.post_status, 'insert', UNIX_TIMESTAMP(now()), 0, 1);
    END IF;
END;

Lo que no puedo entender es cómo verificar si el valor 'post_type' existe en otra tabla y si no lo hace, inserte.

?

¿Fue útil?

Solución

DROP TRIGGER IF EXISTS post_queue_insert;
CREATE TRIGGER post_queue_insert AFTER INSERT ON posts
FOR EACH ROW BEGIN
    DECLARE found_it INT;
    IF (NEW.post_type != 'revision' AND NEW.post_status != 'auto-draft') THEN
        SELECT COUNT(1) INTO found_it FROM some_other_table
        WHERE post_type = NEW.post_type;
        IF found_it = 0 THEN
            INSERT INTO event_queue (action_id, action_do, action_key, action_value, action_event, action_timestamp, sync_complete, SITE_ID) VALUES (NEW.ID, 'post', NEW.post_type, NEW.post_status, 'insert', UNIX_TIMESTAMP(now()), 0, 1);
        END IF;
    END IF;
END;

Si FUND_IT = 0, la fila no contiene un valor que coincida con New.Post_Type.

Darle una oportunidad !!!

Otros consejos

DROP TRIGGER IF EXISTS post_queue_insert;
CREATE TRIGGER post_queue_insert AFTER INSERT ON posts
FOR EACH ROW BEGIN
    IF  ( NEW.post_type != 'revision' 
      AND NEW.post_status != 'auto-draft'
      AND NOT EXISTS
          ( SELECT * 
            FROM other_table
            WHERE post_type = NEW.post_type
          )
        )
    THEN
        INSERT INTO event_queue (action_id, action_do, action_key, action_value, action_event, action_timestamp, sync_complete, SITE_ID) 
        VALUES (NEW.ID, 'post', NEW.post_type, NEW.post_status, 'insert', UNIX_TIMESTAMP(now()), 0, 1);
    END IF;
END;
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