Use the divmod
function.
>>> a, b = divmod(23, 10)
>>> a, b
(2, 3)
>>> print "Tens: %d\nOnes: %d" % divmod(23, 10)
Tens: 2
Ones: 3
Don't know about divmod
? help
is your friend!
>>> help(divmod)
Help on built-in function divmod in module __builtin__:
divmod(...)
divmod(x, y) -> (quotient, remainder)
Return the tuple ((x-x%y)/y, x%y). Invariant: div*y + mod == x.