Increment the last digit of a number

Question

VB2010 I have a user form where the user inputs a number format. The routine then cycles through a list of number pairs and displays them in a list of categories:

 User format "0.00"
                            0.00 - 164.04
                            164.04 - 410.10
                            410.10 - 820.21

What I am trying to do is to increment the first value by one digit so there is no overlap. something like:

                            0.00 - 164.04
                            164.05 - 410.10
                            410.11 - 820.21

I am trying to make it so it works with any number format the user inputs like "0.000" or "0.0". What I currently have is (example for value 164.04)

1. Convert the value to a string "164.04"
2. Take the right most character "4" and convert to an integer 4
3. Increment the integer value by 1 to get 5
4. Take the characters in the string from step #1 except the last and then append
   the integer from Step #3 as a string to get "164.05".

Seemed to work in my VB6 program but wanted to see if anyone had any better ideas. I also don't think i accounted for the last digit being a 9.

Update: based on the suggestions below what ended up working for positive and negative numbers and integers and floats was the following:

Dim p As Integer
Dim numAsStr As String = num.ToString(fmt)
If numAsStr.IndexOf(".") = -1 Then
    p = 0
Else
    p = numAsStr.Length - numAsStr.IndexOf(".") - 1
End If
Dim result as Double = ((num* (10 ^ p) + 1.0) / (10 ^ p))

Answer 1

Here is the algorithm:

1.Find decimal points (p)

2.multiply the number by 10^p, increase it by one, divide it back by 10^p

Dim numAsStr As String = num.ToString()
Dim p As Integer = numAsStr.Length - numAsStr.IndexOf(".") - 1
Dim numInt as Integer = 10^p * num
Dim result as Double = ((10^p *num + 1.0) / 10^p).ToString()

Answer 2

Use "ON ERROR RESUME NEXT" construct for this problem.