Pregunta

In PyroCMS 2.2.3, I want to programaticly login a user once they have activated.

To handle the event I created this in the events file.

But I want to know how to login this user after they activate. I have the $id, but what other variables need to be set?

//inside constructor
Events::register('post_user_activation', array($this, 'evt_post_user_activation'));

....

public function evt_post_user_activation($id) 
{

     $this->ci->current_user = $this->log_in_user($id);

}

private function log_in_user($id)
{

     $this->ci->current_user->id = $id;
}
¿Fue útil?

Solución

I did something similiar however I was able to activate automatically because the users were paying customers. I created a new registration controller and actually duplicated the registration funciton from the user controller. Then the following function made this very easy.

$this->ion_auth->login($user->email, $user->password);

By digging into the ion_auth library and module in "systems/cms/modules/users/" THe ion_auth login function ultimatly sets the following session data

$this->session->set_userdata(array(
            'username'             => $user->username,
            'email'                => $user->email,
            'id'                   => $user->id, //kept for backwards compatibility
            'user_id'              => $user->id, //everyone likes to overwrite id so we'll use user_id
            'group_id'             => $user->group_id,
            'group'                => $group_row->name
));

It creates the user object with the following query

$this->db->select('username, email, id, password, group_id')
    ->where(sprintf('(username = "%1$s" OR email = "%1$s")', $this->db->escape_str($identity)));

if (isset($this->ion_auth->_extra_where))
{
    $this->db->where($this->ion_auth->_extra_where);
}

$query = $this->db->where('active', 1)
    ->limit(1)
    ->get($this->tables['users']);

$user = $query->row();
Licenciado bajo: CC-BY-SA con atribución
No afiliado a StackOverflow
scroll top