Nstimer userinfo.¿Cómo se pasa el objeto al selector?

Question

Tengo este código:

-(void)startRotation:(RDUtilitiesBarRotation)mode {
    rotationTimer = [NSTimer scheduledTimerWithTimeInterval:0.1f target:self selector:@selector(rotateSelectedItem:) userInfo:[NSNumber numberWithInt:mode] repeats:YES];
}
-(void)rotateSelectedItem:(NSNumber*)sender {
    float currAngle = [selectedItem currentRotation];
    if ([sender intValue] == RDUtilitiesBarRotationLeft) {
        [selectedItem rotateImage:currAngle - 1];
    }
    else {
        [selectedItem rotateImage:currAngle + 1];
    }
}
-(void)stopRotation {
    [rotationTimer invalidate];
    rotationTimer = nil;
}

El objetivo es comenzar a girar una vista mientras el usuario tiene un botón.Cuando el usuario lo libera, el temporizador se detendrá.

pero estoy dando esto:

- [__ __ NSCFTIMER INTVALUE]: Selector no reconocido enviado a la instancia 0x4ae360

Pero si estoy empatando en la clase userinfo a nsnumber, ¿por qué estoy recibiendo el temporizador?

gracias.

Answer 1

Your timer action method should look like this

-(void)rotateSelectedItem:(NSTimer*)sender

You can get at the userInfo by doing

NSNumber *userInfo = sender.userInfo;

Answer 2

You misunderstood the signature of the selector that you register with the timer. The sender is NSTimer*, not the userInfo object that you pass into its constructor:

-(void)rotateSelectedItem:(NSTimer*)sender
{
    float currAngle = [selectedItem currentRotation];
    if ([sender.userInfo intValue] == RDUtilitiesBarRotationLeft)
    {
        [selectedItem rotateImage:currAngle - 1];
    }
    else
    {
        [selectedItem rotateImage:currAngle + 1];
    }
}

Answer 3

From the documentation:

The message to send to target when the timer fires. The selector must have the following signature:

- (void)timerFireMethod:(NSTimer*)theTimer