Google Mock - usando :: Testing :: An ()
-
15-11-2019 - |
Pregunta
Recibo un error de compilación mientras usa la siguiente Google Mock Declaración:
EXPECT_CALL(some_object, someFunction(1,An<AStructIDefined>()))
.Times(2);
El error es:
1>ClCompile:
1> TestMyClass.cpp
1>TestMyClass.cpp(189): error C2664: 'mynamespace::MockMyClassClient::gmock_someFunction' : cannot convert parameter 2 from 'testing::Matcher<T>' to 'const testing::Matcher<T> &'
1> with
1> [
1> T=mynamespace::AStructIDefined
1> ]
1> and
1> [
1> T=const mynamespace::AStructIDefined &
1> ]
1> Reason: cannot convert from 'testing::Matcher<T>' to 'const testing::Matcher<T>'
1> with
1> [
1> T=mynamespace::AStructIDefined
1> ]
1> and
1> [
1> T=const mynamespace::AStructIDefined &
1> ]
1> No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
¿Qué estoy haciendo mal?
Actualizaciones:
Estoy usando vs2010.
La Declaración de algunafunción es:
virtual void someFunction( long long ll, const AStructIDefined& a_struct);
an () es un Google Mock Combinador de comodines con lo siguienteDefinición:
// Creates a matcher that matches any value of the given type T.
template <typename T>
inline Matcher<T> An() { return A<T>(); }
Una versión simplificada pero representativa de la estructura es:
namespace mynamespace {
class ABaseCLass
{
public:
virtual ~ABaseCLass(){};
virtual bool isValid() const = 0;
};
struct AStructIDefined : public ABaseCLass
{
public:
OrderStatusReport(SomeEnum1 e_, int i_, double d_);
SomeEnum1 e;
int i;
double d;
const std::string toString() const;
bool isSane() const;
bool operator== (const SomeEnum1& ref_) const;
double getD() const;
int getI() const;
bool isCondition() const;
};
} // namespace mynamespace
Solución
The solution was to change the declaration from:
EXPECT_CALL(some_object, someFunction(1,An<AStructIDefined>()))
.Times(2);
to
EXPECT_CALL(some_object, someFunction(1,An<const AStructIDefined &>()))
.Times(2);
C++ implicitly casts const
and reference &
on function parameters, but google mock's declaration seems to require the type appearing in the function's signature and not the type submitted as a parameter to the function.