How can I compare just the dates of datetime in SQLAlchemy?

Question

I have a query in SQLAlchemy:

weekly_schedule = WeeklyHour.query.filter(
    and_(
        WeeklyHour.start_time.in_(week_dates),
        WeeklyHour.end_time.in_(week_dates),
        WeeklyHour.employee == employee
        )
    ).all()

I am getting the dates of the current week like so:

today = datetime.datetime.today()
week_dates = [today + datetime.timedelta(days=i) for i in xrange(0 - today.weekday(), 7 - today.weekday())]

This returns a list of the current week in datetimes. Like so:

[datetime.date(2014, 4, 7), datetime.date(2014, 4, 8), datetime.date(2014, 4, 9), datetime.date(2014, 4, 10), datetime.date(2014, 4, 11), datetime.date(2014, 4, 12), datetime.date(2014, 4, 13)]

The problem is that the WeeklyHour is a datetime when the employee started and ended that day. And week_dates are a specific time set to now(). I will never get results because the time of the datetime won't match. All I really want to compare is the date portion of the datetime. My current solution (which works but is dumb) is to store separate dates of the datetime.

Answer 1

Rather than querying "in" all days of the week use the days as limits.

today = date.today()
start_of_week = today - timedelta(days=today.weekday())
start_of_following_week = start_of_week + timedelta(days=7)

weekly_schedule = WeeklyHour.query.filter(
    and_(
        WeeklyHour.start_time >= start_of_week,  # On or after Monday
        WeeklyHour.end_time < start_of_following_week, # Before next Monday
        WeeklyHour.employee == employee
        )
    ).all()