IA32 indexed addressing mode without base address
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24-02-2021 - |
Pregunta
What does this syntax mean? I'm specifically unsure about the missing base address
mov 0x804a1d4(,%edx,4),%eax
Solución
assign the contents of 0x804a1d4 + %edx*4
to %eax
Otros consejos
There is no base. Either the base register or the offset register (but not both) may be omitted. In this case the base address is hard-coded and the value to be moved into eax is loaded from
0x804a1d4 + (edx * 4)
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