HTTP GET en VB.NET

Question

¿Cuál es la mejor manera de emitir un http get en VB.net?Quiero obtener el resultado de una petición como http://api.hostip.info/?ip=68.180.206.184

Answer 1

En VB.NET:

Dim webClient As New System.Net.WebClient
Dim result As String = webClient.DownloadString("http://api.hostip.info/?ip=68.180.206.184")

En C#:

System.Net.WebClient webClient = new System.Net.WebClient();
string result = webClient.DownloadString("http://api.hostip.info/?ip=68.180.206.184");

Answer 2

Puede utilizar la clase HttpWebRequest para realizar una petición y recuperar una respuesta de una determinada URL.Usted va a utilizar como:

Try
    Dim fr As System.Net.HttpWebRequest
    Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")         

    fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
    If (fr.GetResponse().ContentLength > 0) Then
        Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
        Response.Write(str.ReadToEnd())
        str.Close(); 
    End If   
Catch ex As System.Net.WebException
   'Error in accessing the resource, handle it
End Try

HttpWebRequest es detallada en: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

Una segunda opción es utilizar la clase WebClient, esto proporciona un fácil de usar interfaz para la descarga de los recursos de la web, pero no es tan flexible como HttpWebRequest:

Sub Main()
    'Address of URL
    Dim URL As String = http://whatever.com
    ' Get HTML data
    Dim client As WebClient = New WebClient()
    Dim data As Stream = client.OpenRead(URL)
    Dim reader As StreamReader = New StreamReader(data)
    Dim str As String = ""
    str = reader.ReadLine()
    Do While str.Length > 0
        Console.WriteLine(str)
        str = reader.ReadLine()
    Loop
End Sub

Más info en el webclient se puede encontrar en: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

Answer 3

El uso de la WebRequest clase

Esto es para obtener una imagen:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Answer 4

La forma más fácil es System.Net.WebClient.DownloadFile o DownloadString.

Answer 5

Usted debe tratar de la HttpWebRequest clase.

Answer 6

Intente esto:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Lo siento por el C#, sé que usted pidió para VB, pero yo no tenía tiempo para convertir.

Answer 7

Public Function getLoginresponce(ByVal email As String, ByVal password As String) As String
    Dim requestUrl As String = "your api"
    Dim request As HttpWebRequest = TryCast(WebRequest.Create(requestUrl), HttpWebRequest)
    Dim response As HttpWebResponse = TryCast(request.GetResponse(), HttpWebResponse)
    Dim dataStream As Stream = response.GetResponseStream()
    Dim reader As New StreamReader(dataStream)
    Dim responseFromServer As String = reader.ReadToEnd()
    Dim result = responseFromServer
    reader.Close()
    response.Close()
    Return result
End Function