Does Mule FunctionalTestCase needs org.junit.rules.TestRule class to run

Question

I'm trying to run a simple Functional test in Mule 3.3. Below is my sample code:

import java.util.Map;    
import org.junit.Test;
import org.mule.api.MuleMessage;
import org.mule.api.client.MuleClient;
import org.mule.tck.junit4.FunctionalTestCase;
import static org.junit.Assert.*;

public class SoapServiceTest extends FunctionalTestCase {

    @Override
    protected String getConfigResources() {
        return "mule-config.xml,core-config.xml";
    }       

    @Test
    public void testSend() throws Exception
    {
        MuleClient client = muleContext.getClient();
        String payload = "foo";
        Map<String, Object> properties = null;
        MuleMessage result = client.send("http://localhost:61005/service", payload, properties);
        assertNotNull(result.getPayloadAsString());
    }    
}

But it complains java.lang.NoClassDefFoundError: org/junit/rules/TestRule. I've junit4.8.1.jar in my classpath but that doesn't have TestRule class which guess is junit4.9 onwards.

Does Mule needs this class? I'm not using any of the annotations of TestRule

Answer 1

From Mule's parent POM:

<dependency>
    <groupId>junit</groupId>
    <artifactId>junit</artifactId>
    <version>4.9</version>
</dependency>

So yes, Mule relies on JUnit 4.9, whether you depend on it directly or not.

When you add:

<dependency>
    <groupId>org.mule.tests</groupId>
    <artifactId>mule-tests-functional</artifactId>
    <version>3.3.1</version>
    <scope>test</scope>
</dependency>

to your project's POM, JUnit 4.9 should be pulled in for you.