Pregunta

For example:

template<unsigned number>
struct A
{
    template<class T>
    static void Fun()
    {}
};

And want to specialize A<1>::Fun()

template<>
A<1>::Fun<int>()
{
    /* some code here. */
}

doesn't work. How to do it? Thanks.

¿Fue útil?

Solución

First of all, you forgot to specify the return type of the function (void). Secondly, you need to have two template<>: one because you are explicitly specializing the class template, and one because you are explicitly specializing its member function template.

Therefore, this is the correct syntax:

template<> // Because you are explicitly specializing the A class template
template<> // Because you are explicitly specializing the `Fun()` member template
void A<1>::Fun<int>()
{
    /* some code here. */
}
Licenciado bajo: CC-BY-SA con atribución
No afiliado a StackOverflow
scroll top