How to extract a common name from multipal filenames and delete something I don't want

StackOverflow https://stackoverflow.com/questions/17679699

  •  03-06-2022
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Pregunta

For example, I have 7 files named:

g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt
g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt
g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt
g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt
g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt
g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt
g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt

I want to extract a name from these files, named as:

 g18_84pp_2A_MVP_GoodiesT0_MIX.txt

Any idea for this? Thanks.

Is there any possible that I can only depend on the underscores?

For example, separating filename as

"g18_84pp_2A_MVP2", "_", "GoodiesT0-HKJ-DFG" "_", "MIX-CMVP2_Y1000-MIX", ".txt". 

Take "g18_84pp_2A_MVP2" without number 2, take "GoodiesT0" from "GoodiesT0-HKJ-DFG" and take first "MIX" from "MIX-CMVP2_Y1000-MIX", B/C I have a lot of files have different names for separating parts, I want it general as well

¿Fue útil?

Solución

import re
names = ['g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt',
'g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt',
'g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt',
'g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt',
'g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt',
'g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt',
'g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt']

f = lambda x: re.findall('g18_84pp_2A_MVP(.*?)_GoodiesT0(.*?)_MIX(.*?)\.txt', x)

for x in names:
    print(f(x))

Produces

[('1', '-HKJ-DFG', '-CMVP1_Y1000-MIX')]
[('2', '-HKJ-DFG', '-CMVP2_Y1000-MIX')]
[('3', '-HKJ-DFG', '-CMVP3_Y1000-MIX')]
[('4', '-HKJ-DFG', '-CMVP4_Y1000-MIX')]
[('5', '-HKJ-DFG', '-CMVP5_Y1000-MIX')]
[('6', '-HKJ-DFG', '-CMVP6_Y1000-MIX')]
[('7', '-HKJ-DFG', '-CMVP7_Y1000-MIX')]

Filter the names that doesn't match this pattern:

names = list(filter(f, names))

Since it's unclear what you're trying to do, this is going to be a good starting point.

UPDATE

The question was updated. Here is what you (probably) want to achieve:

import re
names = ['g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt',
'g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt',
'g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt',
'g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt',
'g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt',
'g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt',
'g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt']

expression = 'g18_84pp_2A_MVP(.*?)_Goodies(.*?)_MIX(.*?)\.txt'
f = lambda x: re.findall(expression, x)
_f = lambda x: len(re.findall(expression, x))==3

for x in names:
    print(f(x))

Outputs

[('1', 'T0-HKJ-DFG', '-CMVP1_Y1000-MIX')]
[('2', 'T0-HKJ-DFG', '-CMVP2_Y1000-MIX')]
[('3', 'T0-HKJ-DFG', '-CMVP3_Y1000-MIX')]
[('4', 'T0-HKJ-DFG', '-CMVP4_Y1000-MIX')]
[('5', 'T0-HKJ-DFG', '-CMVP5_Y1000-MIX')]
[('6', 'T0-HKJ-DFG', '-CMVP6_Y1000-MIX')]
[('7', 'T0-HKJ-DFG', '-CMVP7_Y1000-MIX')]

If you need to filter the original list:

names = list(filter(_f, names))
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