First of all, your R code doesn't work as written. I would suggest copy-pasting it into a clean session, and if it errors out for you as well, correcting syntax errors or including add-on libraries until it runs.
That said, I assume that you are supposed to end up with a data.frame
of two-dimensional numeric coordinates. So, for the purposes of binning and counting them, any such data will do, so I took the liberty of simulating such a dataset. Please correct me if this doesn't capture a relevant aspect of your data.
## Skip this line if you are the OP, and substitute the real data instead.
data<-data.frame(LATITUDE=runif(100,1,100),LONGITUDE=runif(100,1,100));
## Add the latitudes and longitudes between which each observation is located
## You can substitute any number of breaks you want. Or, a vector of fixed cutpoints
## LATgrid and LONgrid are going to be factors. With ugly level names.
data$LATgrid<-cut(data$LATITUDE,breaks=10,include.lowest=T);
data$LONgrid<-cut(data$LONGITUDE,breaks=10,include.lowest=T);
## Create a single factor that gives the lat,long of each observation.
data$IDgrid<-with(data,interaction(LATgrid,LONgrid));
## Now, create another factor based on the above one, with shorter IDs and no empty levels
data$IDNgrid<-factor(data$IDgrid);
levels(data$IDNgrid)<-seq_along(levels(data$IDNgrid));
## If you want total grid-cell count repeated for each observation falling into that grid cell, do this:
data$count<- ave(data$LATITUDE,data$IDNgrid,FUN=length);
## You could have also used data$LONGITUDE, doesn't matter in this case
## If you want just a table of counts at each grid-cell, do this:
aggregate(data$LATITUDE,data[,c('LATgrid','LONgrid','IDNgrid')],FUN=length);
## I included the LATgrid and LONgrid vectors so there would be some
## sort of descriptive reference accompanying the anonymous numbers in IDNgrid,
## but only IDNgrid is actually necessary
## If you want a really minimalist table, you could do this:
table(data$IDNgrid);