Pregunta

I am working on a web page where I am using Impromptu Api for dialogbox which includes html form :

            html = '<label>Name&nbsp;&nbsp;&nbsp;&nbsp;<input type="text" id="fname" name="fname" value="'+STUDENT_NAME+'"></label><br />'
                        + '<label>Sex<select id="sex"> <option value="m" >Male</option>   <option value="f" selected>Female</option>'
                        + '</select>'
                        + '</label><br />'
                        + '<label>Category<select id="cat"> <option value="a">A</option>   <option value="b" selected>B</option>'
                        + '</select>' + '</label>'+
                        '<input type="file" id="logo">'+ 
                        '<br />';

Using Ajax for submitting the form like this:

         $.ajax({
                        url : 'AddStudent.jsp',
                        data : 'classId=' +
                                 <%=class_id%>
                                + '&name='
                                + document.getElementById('fname').value
                                + '&cat='
                                + document.getElementById('cat').value
                                + '&func=del' + '&sex='
                                + document.getElementById('sex').value,
                        type : 'post',
                        success : function(msg) {
                                              //events}

I have got the code to upload a file like this:

             String saveFile = "";
  String contentType = request.getContentType();
  if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) {
        DataInputStream in = new DataInputStream(request.getInputStream());
        int formDataLength = request.getContentLength();
        byte dataBytes[] = new byte[formDataLength];
        int byteRead = 0;
        int totalBytesRead = 0;
        while (totalBytesRead < formDataLength) {
              byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
              totalBytesRead += byteRead;
        }
        String file = new String(dataBytes);
        saveFile = file.substring(file.indexOf("filename=\"") + 10);
        saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
        saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1, saveFile.indexOf("\""));
        int lastIndex = contentType.lastIndexOf("=");
        String boundary = contentType.substring(lastIndex + 1, contentType.length());
        int pos;
        pos = file.indexOf("filename=\"");
        pos = file.indexOf("\n", pos) + 1;
        pos = file.indexOf("\n", pos) + 1;
        pos = file.indexOf("\n", pos) + 1;
        int boundaryLocation = file.indexOf(boundary, pos) - 4;
        int startPos = ((file.substring(0, pos)).getBytes()).length;
        int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
        saveFile = "D:/SERVERE/" + saveFile;
        File ff = new File(saveFile);
        FileOutputStream fileOut = new FileOutputStream(ff);
        fileOut.write(dataBytes, startPos, (endPos - startPos));
        fileOut.flush();
        fileOut.close();

  }

But this wont work with the Ajax method . I want the file must be uploaded on the same page. How could this be done using Ajax or is there any other technique?Please help

¿Fue útil?

Solución

If you can use the HTML5 File API and the FormData Object.

var xhr = new XMLHttpRequest();
xhr.upload.addEventListener('progress',function(ev){
    console.log((ev.loaded/ev.total)+'%');
}, false);
xhr.onreadystatechange = function(ev){
    // Blah blah blah, you know how to make AJAX requests
};
xhr.open('POST', url, true);
var files = document.getElementById('logo').files;
var data = new FormData();
for(var i = 0; i < files.length; i++) data.append('file'+i, files[i]);
xhr.send(data);

You can do data.append('name', document.getElementById('name')) etc. to append all the other form fields.

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