Question

I am trying to optimize an objective function using integer programming, I have to use Max operator in my function, I want to know is there any way to deal with that?

Actually my question is similar to Using min/max within an Integer Linear Program but is different in some aspects:

  • All variables are binary.
  • Note that x4 and x5 are presented in two place.
  • One possible solution is using auxiliary variables like the answer of similar question, but I am confused when using this solution for my example.

Example:

Minimize (c1 * x1) + (c2 * x2) + (c3 * x3) + Max(c4 * x4, c5 * x5) + (c6 * x4) + (c7 * x5)

subject to
some equality and inequality constraints

Était-ce utile?

La solution

Use the approach in the question you linked. The expression

Max(c4 * x4, c5 * x5)

can be replaced by a variable x6, provided that you add the following additional constraints:

x6 >= c4 * x4
x6 >= c5 * x5

So you total set becomes:

Minimize (c1 * x1) + (c2 * x2) + (c3 * x3) + x6 + (c6 * x4) + (c7 * x5)

subject to:

some equality and inequality constraints

and the new requirements:

x6 >= c4 * x4
x6 >= c5 * x5

This works since Max(c4 * x4, c5 * x5) will either take the value c4 * x4 or c5 * x5. The introduced variable x6 will always be larger or equal to both of these expressions, and so will always be larger or equal to the total max-expression. When properly minimized, x6 will bottom out at the value of the max-expression. So when minimized, the two forms are equivalent.

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