Question

/.*?/.exec("abc");//output [""]

I think .*? is non-greedy and it should return a

Était-ce utile?

La solution

Well that is expected since .* means 0 or more and by putting ? you make it non-greedy hence it match an empty string.

If you want to match a then you should use:

 /.+?/.exec("abc");

DIfference is + instead of * which means match 1 or more characters using non-greedy quantifier.

Autres conseils

By using * instead of e.g. + you allowed for matching empty string as a non-greedy option.

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