Python: Get Twitter Trends in tweepy, and parse JSON

Question

Ok, so please note this is my first post

So, I am trying to use Python to get Twitter Trends, I am using python 2.7 and Tweepy.

I would like something like this (which works):

#!/usr/bin/python
# -*- coding: utf-8 -*-
import tweepy
consumer_key = 'secret'
consumer_secret = 'secret'
access_token = 'secret'
access_token_secret = 'secret'
# OAuth process, using the keys and tokens
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
api = tweepy.API(auth)
trends1 = api.trends_place(1)

print trends1

That gives a massive JSON string,

I would like to extract each trend name to a variable, in string format str(trendsname) ideally.

Which would ideally have the names of trends like so: trendsname = str(trend1) + " " +str(trend2) + " " and so on, for each of the trend names.

Please note I am only learning Python.

Answer 1

It looks like Tweepy deserializes the JSON for you. As such, trends1 is just an ordinary Python list. This being the case, you can simply do the following:

trends1 = api.trends_place(1) # from the end of your code
# trends1 is a list with only one element in it, which is a 
# dict which we'll put in data.
data = trends1[0] 
# grab the trends
trends = data['trends']
# grab the name from each trend
names = [trend['name'] for trend in trends]
# put all the names together with a ' ' separating them
trendsName = ' '.join(names)
print(trendsName)

Result:

#PolandNeedsWWATour #DownloadElyarFox #DünMürteciBugünHaşhaşi #GalatasaraylılıkNedir #KnowTheTruth Tameni Video Anisa Rahma Mikaeel Manado JDT

Answer 2

I think the following code works fine too:

trends1 = api.trends_place(1)
trends = set([trend['name'] for trend in trends1[0]['trends']])
print trends