The correct format specifier for double
is %lf
, not %f
.
C language: scanf function producing different results with float and double types?
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19-10-2022 - |
Question
**Code A returns the correct conversion: 6.55957.**
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
float convert(float currencyA)
{
float currencyB = 0;
currencyB = 6.55957 * currencyA;
return currencyB;
}
int main(int argc, const char *argv[])
{
float amount = 0;
printf("How much\n");
scanf("%f", &amount);
printf("You get %f in currencyB", convert(amount));
return 0;
}
**Code B returns an incorrect conversion: 0.051247.**
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
double convert(double currencyA)
{
double currencyB = 0;
currencyB = 6.55957 * currencyA;
return currencyB;
}
int main(int argc, const char *argv[])
{
double amount = 0;
printf("How much\n");
scanf("%f", &amount);
printf("You get %f in currencyB", convert(amount));
return 0;
}
If I remove printf and scanf, and assign 1 as the value to the "amount" variable the result is correct.
I suspect scanf is causing the error. If so, why would that be?
Thank you for reading and feel free to ask for any additional info you require.
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