Question

So I have this code snippet to translate a string into bitset.

    String huffmancode = "0010110100";
    char[] ch = huffmancode.toCharArray();

    BitSet bs = new BitSet();
    for (int i = 0; i < ch.length; i++)  {
        if (ch[i] == '1') {
            bs.set(i);
        }
    }

My question is how to determine the boundary / size / length of the bitset given that the first and the last indexes of huffman code were 0's ?

Était-ce utile?

La solution

The following bitset contains [0,1] in order and the last line of the following code prints out 2, the length of the bitset.

BitSet bs = new BitSet();

bs.set(0, false);
bs.set(1, true);

System.out.println(bs.length());
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