Check this out. Let's take for example your formula:
=IF(IFERROR(FIND("/",A1),0)>0,DATE(MID(A1,7,4),LEFT(A1,2),MID(A1,4,2)),DATE(TEXT(A1,"yyyy"),TEXT(A1,"dd"),TEXT(A1,"mm")))
VBA equivalent functions:
Find = Instr
Date = DateSerial
Text = Format (not exactly the same but the nearest)
Code equivalent:
Dim mydate As Date
Dim myformat As String
myformat = "mm/dd/yyyy hh:mm AM/PM"
If InStr(1, [A1], "/") > 0 Then
mydate = DateSerial(Mid(Format([A1], myformat), 7, 4), _
Left(Format([A1], myformat), 2), Mid(Format([A1], myformat), 4, 2))
Else
mydate = DateSerial(Year([A1]), Month([A1]), Day([A1]))
End If
[B1] = mydate
Take note that [A1]
is a shortcut Evaluate
function which can also be written as Evaluate("A1")
.
I used that to refer to Cell A1 as in your formula. You can use the conventional Range Object
reference like this: Range("A1")
. I used the shortcut because it looks cleaner. But it is not advisable in huge data sets.
For your time formula:
=IF(IFERROR(FIND("/",A1),0)>0,TIME(MID(A1,12,2),MID(A1,15,2),"00"),TEXT(A1,"h:mm AM/PM"))
Code Equivalent:
Dim mytime As Date
If InStr(1, [A1], "/") > 0 Then
mytime = TimeValue([A1])
Else
'~~> myformat is declared above
mytime = TimeValue(Format([A1], myformat))
End If
[C1] = mytime
You can also check the format of the cell like below:
Select Case True
Case [A1].NumberFormat = "General"
mydate = DateSerial(Year([A1]), Month([A1]), Day([A1]))
mytime = TimeValue(Format([A1], myformat))
Case [A1].NumberFormat = myformat '~~> again this is declared above
mydate = DateSerial(Mid(Format([A1], myformat), 7, 4), _
Left(Format([A1], myformat), 2), Mid(Format([A1], myformat), 4, 2))
mytime = TimeValue([A1])
Case Else
MsgBox "Invalid Format. Cannot be evaluated"
End Select
[B1] = mydate: [C1] = mytime
Not sure if above will really solve your problem.
There are just many possibilities when you extract datetime stamp from a database.
If the scenarios you mentioned are only the problems you encounter, then above solutions might work.