Résolution du code d'erreur: 1005. Impossible de créer la table '' (Errno: 150) Erreur

Question

Je crée en suivant trois tables dans MySQL

1. Maître de poste
2. PUBLICITÉ
3. Candidatemain

Voici les instructions de création

Maître de poste

CREATE TABLE `postmaster` (
  `POSTCODE` int(2) NOT NULL DEFAULT '0',
  `POSTNAME` varchar(250) DEFAULT NULL,
  PRIMARY KEY (`POSTCODE`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

PUBLICITÉ

CREATE TABLE `advertisment` (
  `ADVTNO` varchar(35) NOT NULL,
  `ADVTDATE` date NOT NULL,
  `POSTCODE` int(2) NOT NULL,
  `ADVTOPENDATE` date NOT NULL COMMENT 'ADVERTISEMENT OPENING DATE',
  `ADVTCLOSEDATE` date NOT NULL COMMENT 'ADVERTISEMENT CLOSING DATE',
  `EDITCLOSEDATE` date NOT NULL COMMENT 'CLOSING DATE FOR EDITING APPLICATION',
  `LASTREPRINTDATE` date NOT NULL COMMENT 'LAST DATE FOR REPRINTING APPLICATION',
  `FEESCST` int(4) NOT NULL COMMENT 'FEE FOR SC/ST CATEGORY',
  `FEESTAFF` int(4) DEFAULT NULL COMMENT 'FEE FOR STAFF ',
  `FEEOBC` int(4) DEFAULT NULL COMMENT 'FEE FOR OBC CATEGORY',
  `ADVOCATEEXPERIENCE` int(2) DEFAULT NULL,
  PRIMARY KEY (`ADVTNO`,`ADVTDATE`,`POSTCODE`),
  KEY `fk_post` (`POSTCODE`),
  CONSTRAINT `fk_post` FOREIGN KEY (`POSTCODE`) REFERENCES `postmaster` (`POSTCODE`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1

Tout jusqu'à ce que je sois bien mais quand je vais pour la création du CANDIDATEMAIN Tableau I reçoit une erreur

Voici la création de déclaration de Candidatemain

CREATE TABLE `candidatemain` (

  `ADVTNO` varchar(35) NOT NULL DEFAULT '',
  `ADVTDATE` date NOT NULL DEFAULT '0000-00-00',
  `POSTCODE` int(2) NOT NULL DEFAULT '0',
  `REGISTRATIONNO` int(6) NOT NULL DEFAULT '0',
  `SALUTATION` varchar(10) NOT NULL,
  `FULLNAME` varchar(90) NOT NULL,
  `SURNAME` varchar(30) DEFAULT NULL,
  `NAME` varchar(30) NOT NULL,
  `LASTNAME` varchar(30) DEFAULT NULL,
  `LASTUPDATEDIP` varchar(20) NOT NULL DEFAULT '',
  `LASTUPDATEDDATE` date DEFAULT NULL,
  `ENTRYDATE` date NOT NULL,
  PRIMARY KEY (`ADVTNO`,`ADVTDATE`,`POSTCODE`,`REGISTRATIONNO`),
  KEY `FK_ADVT` (`ADVTNO`, `ADVTDATE`,`POSTCODE`) ,
  CONSTRAINT `FK_ADVT` FOREIGN KEY (`ADVTNO`, `ADVTDATE`,`POSTCODE`) REFERENCES `advertisment` (`ADVTNO`, `ADVTDATE`,`POSTCODE`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

L'erreur que j'obtiens est:

Error Code: 1005. Can't create table 'dbName.candidatemain' (errno: 150)

Quelle pourrait être la raison de cette erreur?

MySQL Verion: mysql ver 14.14 Distrib 5.1.53, pour win64

Answer 1

Créer advertisment table avec charset par défaut comme utf8;

Latin1 Les colonnes ne sont pas équivalentes à UTF8 Colonnes. Ainsi, la contrainte de clé étrangère ne peut pas se former correctement. D'où le 1005 (ER_CANT_CREATE_TABLE) Erreur.

Voici mon journal MySQL.

mysql> CREATE TABLE `advertisment` (
    ->   `ADVTNO` varchar(35) NOT NULL,
    ->   `ADVTDATE` date NOT NULL,
    ->   `POSTCODE` int(2) NOT NULL,
    ->   `ADVTOPENDATE` date NOT NULL COMMENT 'ADVERTISEMENT OPENING DATE',
    ->   `ADVTCLOSEDATE` date NOT NULL COMMENT 'ADVERTISEMENT CLOSING DATE',
    ->   `EDITCLOSEDATE` date NOT NULL COMMENT 'CLOSING DATE FOR EDITING APPLICATION',
    ->   `LASTREPRINTDATE` date NOT NULL COMMENT 'LAST DATE FOR REPRINTING APPLICATION',
    ->   `FEESCST` int(4) NOT NULL COMMENT 'FEE FOR SC/ST CATEGORY',
    ->   `FEESTAFF` int(4) DEFAULT NULL COMMENT 'FEE FOR STAFF ',
    ->   `FEEOBC` int(4) DEFAULT NULL COMMENT 'FEE FOR OBC CATEGORY',
    ->   `ADVOCATEEXPERIENCE` int(2) DEFAULT NULL,
    ->   PRIMARY KEY (`ADVTNO`,`ADVTDATE`,`POSTCODE`),
    ->   KEY `fk_post` (`POSTCODE`),
    ->   CONSTRAINT `fk_post` FOREIGN KEY (`POSTCODE`) REFERENCES `postmaster` (`POSTCODE`)
    -> ) ENGINE=InnoDB DEFAULT CHARSET=utf8; -- <== This little change make it work.
Query OK, 0 rows affected (0.06 sec)

mysql> CREATE TABLE `candidatemain` (
    ->
    ->   `ADVTNO` varchar(35) NOT NULL DEFAULT '',
    ->   `ADVTDATE` date NOT NULL DEFAULT '0000-00-00',
    ->   `POSTCODE` int(2) NOT NULL DEFAULT '0',
    ->   `REGISTRATIONNO` int(6) NOT NULL DEFAULT '0',
    ->   `SALUTATION` varchar(10) NOT NULL,
    ->   `FULLNAME` varchar(90) NOT NULL,
    ->   `SURNAME` varchar(30) DEFAULT NULL,
    ->   `NAME` varchar(30) NOT NULL,
    ->   `LASTNAME` varchar(30) DEFAULT NULL,
    ->   `LASTUPDATEDIP` varchar(20) NOT NULL DEFAULT '',
    ->   `LASTUPDATEDDATE` date DEFAULT NULL,
    ->   `ENTRYDATE` date NOT NULL,
    ->   PRIMARY KEY (`ADVTNO`,`ADVTDATE`,`POSTCODE`,`REGISTRATIONNO`),
    ->   KEY `FK_ADVT` (`ADVTNO`, `ADVTDATE`,`POSTCODE`) ,
    ->   CONSTRAINT `FK_ADVT` FOREIGN KEY (`ADVTNO`, `ADVTDATE`,`POSTCODE`) REFERENCES `advertisment ` (`ADVTNO`, `ADVTDATE`,`POSTCODE`)
    -> ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
Query OK, 0 rows affected (0.12 sec)

Answer 2

Ton FOREIGN KEY CONSTRAINT pour table candidatemain et advertisment a un charme différent, cela provoque l'erreur, laissez-les avoir le même charme.