Program to find greater value between a^n and b^n in C++
https://www.tutorialspoint.com/program-to-find-greater-value-between-a-n-and-b-n-in-cplusplus
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10-09-2020 - |
Question
In this tutorial, we will be discussing a program to find greater value between a^n and b^n.
For this we will be provided with three numbers. Our task is to calculate a^n and b^n and return back the greater of those values.
Example
#include <bits/stdc++.h> using namespace std; //finding the greater value void findGreater(int a, int b, int n){ if (!(n & 1)) { a = abs(a); b = abs(b); } if (a == b) cout << "a^n is equal to b^n"; else if (a > b) cout << "a^n is greater than b^n"; else cout << "b^n is greater than a^n"; } int main(){ int a = 12, b = 24, n = 5; findGreater(a, b, n); return 0; }
Output
b^n is greater than a^n
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