Django reverse url with parameters to a class based view
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23-03-2021 - |
Question
I just started learning python and django and I have a question. I got the assignment to turn function views into class based views. But my links wont work now.
these are from urls.py:
url(r'^$', ContactIndex.as_view()),
url(r'^add$', ContactAdd.as_view()),
url(r'^([0-9]+)/update$', ContactUpdate.as_view()),
url(r'^([0-9]+)/view$', ContactView.as_view()),
This is my link :
{% url rtr_contact.views.ContactView contact.id %}
but this doesnt work it says:
Caught NoReverseMatch while rendering: Reverse for 'rtr_contact.views.ContactView' with arguments '(20L,)' and keyword arguments '{}' not found.
La solution
To make url reversing easy, I recommend that you always name your url patterns.
url(r'^$', ContactIndex.as_view(), name="contact_index"),
url(r'^add$', ContactAdd.as_view(), name="contact_add"),
url(r'^([0-9]+)/update$', ContactUpdate.as_view(), name="contact_update"),
url(r'^([0-9]+)/view$', ContactView.as_view(), name="contact_view"),
Then in the template:
{% url contact_view contact.id %}
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